# Researching automated theorem provers

Lately I’ve been messing around with automated theorem provers. Specifically Prover9.

The moment you open it, if you use the GUI mode, you will see 2 big text boxes – assumptions and goals. Naturally, when playing one starts with simple stuff.

We leave the assumptions blank and set $P \implies (Q \implies P).$ as our goal. If we click Start, we see that it proves it immediately.

% -------- Comments from original proof --------
% Proof 1 at 0.00 (+ 0.00) seconds.
% Length of proof is 2.
% Level of proof is 1.
% Maximum clause weight is 0.
% Given clauses 0.

1 P -> (Q -> P) # label(non_clause) # label(goal). [goal].
2 \$F. [deny(1)].

============================== end of proof ==========================


That was fun, but what stood out for me is that in mathematics we often take axioms for “granted”, i.e. it’s rarely that we ever think about the logic behind it. But with Prover9, we need to express all of it using logic.

For Prover9 there is a general rule, that variables start with u through z lowercase. Everything else is a term (atom).

For start, let’s define set membership. We say $\in$ denotes set membership, and that’s it. Because that’s all there’s to it, it’s like an atom. So let’s say that member(x, y) denotes that.

Now let’s define our sets A = {1}, B = {1, 2}, and C = {1}.

all x ((x = 1) <-> member(x, A)).
all x ((x = 1 | x = 2) <-> member(x, B)).
all x ((x = 1) <-> member(x, C)).


Now if we try to prove member(1, A), it will succeed. But it will not for member(2, A).

What do we know about the equivalence of 2 sets? They are equal if there doesn’t exist an element that is in the first and not in the second, or that is in the second and not in the first.

In other words:

set_equal(x, y) <-> - (exists z ((member(z, x) & - member(z, y)) | (- member(z, x) & member(z, y)))).


So, Prover9 can prove set_equal(A, C), but not set_equal(A, B).

Another example is that we can define the set of the naturals with just:

member(Zero, Nat).
member(x, Nat) -> member(Suc(x), Nat).


So, it can easily prove:
0: member(zero, Nat)
1: member(Suc(Zero), Nat)
2: member(Suc(Suc(Zero)), Nat) (2), etc.

# Relation between strict and non-strict identities

== is value check. For a and b to have the same value, we will say V(a, b). Thus a == b <=> V(a, b).

=== is value+type check. For a and b to have the same type, we will say T(a, b). Thus a === b <=> V(a, b) and T(a, b).

Now, to prove a === b => a == b, suppose that a === b. By the definitions, we have as givens V(a, b) and T(a, b). So we can conclude that V(a, b), i.e. a == b.

The contrapositive form is a != b => a !== b, which also holds.

However, note that the converse form a == b => a === b doesn’t necessarily hold. To see why, suppose a == b, that is V(a, b). Now we need to prove that V(a, b) and T(a, b). We have V(a, b) as a given, but that’s not the case for T(a, b), i.e. the types may not match.

So, whenever you see a === b you can safely assume that a == b is also true. The same holds for when you see a != b, you can safely assume that a !== b 🙂

# Abstractions with Set Theory

Like in programming, building abstractions in mathematics is of equal importance.

We will start with the most basic object (the unordered collection) and work our way up to defining functions.

Set

A set is an unordered collection of objects. This might sound too abstract but that’s what it is. The objects can be anything. It is usually denoted by comma separating the list of objects and enclosing them using curly braces.

For example, one set of fruits is $\{ apple, banana \}$.

Since it is an unordered collection we have that $\{ apple, banana \} = \{ banana, apple \}$.

For membership, we denote $apple \in \{ apple, banana \}$ to say that apple is in that collection.

Tuples

An n-tuple is an ordered collection of n objects. As with sets, the objects can be anything. It is usually denoted by comma separating the list of objects and enclosing them using parenthesis.

We can represent it using unordered collections as follows: Consider the tuple $a = (a_1, a_2, ..., a_n)$. We can use the set $A = \{ \{1, \{a_1\}\}, \{2, \{a_2\}\}, ..., \{n, \{a_n\}\} \}$. Note that here I’m using natural numbers and I assume them to be unique atoms. Otherwise, if we represented naturals in terms of set theory, there would be issues with this definition. For that, we’d have to use Kuratowski’s definition, but we can skip that for simplicity’s sake.

Now to extract the k-th element of the tuple, we can pick x s.t. $\{k, \{x\}\} \in A$.

So now we have that $(a, b) = (c, d) \leftrightarrow a = b \land c = d$, that is two tuples are equal iff their first and second elements respectively are equal. This is what makes tuples ordered.

One example of a tuple is $(1 pm, 2 pm, 3 pm)$ which represents 3 hours of a day sequentially.

Relations

An n-ary relation is just a set of n-tuples with different values. We are mostly interested in binary relations.

One example of such a relation is the “is bigger than”. So we have the following set: $\{ (cat, mouse), (mouse, cheese), (cat, cheese) \}$.

Functions

Now we can define functions in terms of relations.

To do that we first have to discuss subset. A is a subset of B if all elements of A are found in B (but not necessarily vice-versa). We denote it as such: $A \subseteq B$. So for example: $\{ 1, 2 \} \subseteq \{ 1, 2, 3 \}$ and $\{ 1, 2, 3 \} \subseteq \{ 1, 2, 3 \}$. But this doesn’t hold: $\{ 1, 2, 3 \} \subseteq \{ 1, 2 \}$.

So with this, a function is a mapping from a set A to a set B, or in other words it is a subset of all combinations of ordered pairs whose first element is an element of A and second element is an element of B.

For example, if $A = \{ a, b \} \land B = \{ 1, 2, 3 \}$ then the combinations are: $F = \{ (a, 1), (a, 2), (a, 3), (b, 1), (b, 2), (b, 3) \}$. A function f from A to B is denoted $f : A \rightarrow B$ and is a subset of F: $f \subseteq F$.

This combination of pairs is called a Cartessian product, and is defined as the set: $\{ (a, b) \mid a \in A \land b \in B \}$.

We have one more constraint to add to a function, namely that it cannot produce 2 or more different values for a single input. So using either of f(a) = 1 or f(a) = 2 or f(a) = 3 is okay, but not all three of them. That means that we only have to use one of $\{ (a, 1), (a, 2), (a, 3) \}$ from our example set above. The same reasoning goes for b. So $f = \{ (a, 1), (b, 2) \}$ with $f(a) = 1 \land f(b) = 2$ is one valid example.

Conclusion

Matrices (tuples of tuples), lists (sets or tuples), graphs (set of sets), digraphs (set of tuples), trees (graphs) can also be derived similarly.

This is what makes the set a powerful and interesting idea.